Heya ! Using a theoram about triangles , Given a triangle ∆ABC, the sum of the lengths of any two sides of the triangle is greater than the length of the third side , Also , the length of third side always greater than absolute difference of the other two sides , Let the third side be x , So , x < 9 + 8 and x > 9 - 8 x < 17 and x > 1 Hence , x ∈ [ 2 , 17 ] inch. Above case is true for any triangle , be it scalene , Isosceles , Right-angled ... As , for Isosceles , the third side can be 8 or 9 inches , For scalene , all values in the above range satusfies , For right angled triangle , we have 2 cases , Case 1 : Third side is the hypotenuse Then , x = √(9²+8²) = √145 = 12.0415 inch. Case 2 : Third side is not the hypotenuse Then , x = √(9²-8²) = √17 = 4.1231 inch. Hope it helps you ! :)
There are two possible choices for the third side. One is using the 9 as the hypotenuse, and the number less than 9. The second is using the number as they hypotenuse. Remember to use the a² + b² = c² formula. let the hypotenuse side be "x". 9² + 8² = x² Simplify 81 + 64 = x² Add x² = 145 Root both sides √x² = √145 Answerx = <span>12.04159 (rounded) let one of the sides (not hypotenuse) be x 9</span>²- 8² = x² <span>Simplify 81 - 64 = x</span>² Subtract x² = 17 Root both sides to isolate the x √x² = √17 Answerx = 4.12310 (rounded) hope this helps