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2 years ago

What is the rate of change of the linear relationship modeled in the table?

Mathematics

2 answers:

KIM [24]2 years ago

5 0

I think your answer would be 3/2

Genrish500 [490]2 years ago

5 0

~Hello there!

My answer for this question would be 3/2 because when you are determining the rate of change the y always goes over the x value so in this case obviously 3-1 equals 2 and 5-2 equals 3 so just put those values in fraction form and you get 3/2!!

~Hope this helped have a nice day!~

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To earn money for a contest, the math team pays $40 for a box of spirit banners. They sell each banner for $3.50. Write an equat

ankoles [38]

Answer:

$3.5b - 40$ where $b$ is the amount of banners sold.

Step-by-step explanation:

We know the team has already spent $40, and they earn #3.5 per banner.

Hence, with $b$ representing the amount of banners sold, the equation is $3.5b - 40$

7 0

2 years ago

The league championship 800 meter race has 6 runners.

s2008m [1.1K]

Answer: 120

Step-by-step explanation:

Given : The league championship 800 meter race has 6 runners.

The number of positions = 3

Since order matters here , so we use Permutation.

The permutation of n things taking r at a time is given by :-

$^nP_r=\dfrac{n!}{(n-r)!}$

Then, the number of different ways they place first, second, and third :_

$^6P_3=\dfrac{6!}{(6-3)!}=\dfrac{6\times5\times4\times3!}{3!}=120$

Hence, they can place first, second, and third in 120 different ways .

7 0

2 years ago

Is 5 and four fifths = 5.8

nekit [7.7K]

Yes. That's exactly right. Good work.

6 0

3 years ago

Read 2 more answers

Find the inverse of f(x)=1/(x^3)

Pepsi [2]

Answer:

Step-by-step explanation:

y $f(x)^{-1} = inverse\\f(x)=y \\y = 1/(x^{3} \\Inverse: y=x ------------> x = 1/y^{3}\\y^{3} - \frac{1}{x} = 0\\y^{3} = \frac{1}{x}\\y = \sqrt[3]{\frac{1}{x}} \\y = \frac{\sqrt[3]{1} }{\sqrt[3]{x}} \\y = \frac{1}{\sqrt[3]{x}}$

4 0

2 years ago

Ok how is every ones day ok what is 12345 times 23456=

lutik1710 [3]

The answer is 289,564,320. Have a nice day and Happy Holidays

8 0

2 years ago