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1 year ago

10

Help me!

+\sqrt{84} =?" alt="\sqrt{84} +\sqrt{84} =?" align="absmiddle" class="latex-formula">

1 answer:

lukranit [14]1 year ago

8 0

Answer:

18.4

Step-by-step explanation:

Well the square root of 84 isn't an exact answer.

But when rounded it equals to approximately 9.16 or rounded even more 9.2 at most.

So 9.2 + 9.2 = 18.4.

So the answer is ≈ 18.4

Have a good day or night wherever you are. May GOD Bless You!!

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Alborosie

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2 years ago

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

2 years ago

(-9x-3)+6<93 help me out plz

Lunna [17]

Answer:

x>-10

Step-by-step explanation:

(-9x-3) + 6 < 93

-9x-3+6 < 93

-9x + 3 < 93

-9x < 93-3 (subtracting 3 both sides)

Dividing by -9 both sides

x > 90/-9 ( switch the sign because dividing by a negative number)

x> -10 Answer

Hope this helps!

4 0

2 years ago

Factorize: x² + 3x + 2

zvonat [6]

Step-by-step explanation:

x² + 3x + 2

x² + x + 2x + 2 because 1+2=3 and 2×1=2

By taking out common terms, we get

x(x+1)+2(x+1)

(x+1)(x+2)

7 0

2 years ago

What is the following product

Genrish500 [490]

For this case we must find the product of the following expression:

$\sqrt [3] {5} * \sqrt {2}$

By definition of properties of powers and roots we have:

$\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}$

We rewrite the expression using the lowest common index of 6, then:

$5 ^ {\frac {1} {3}} * 2 ^ {\frac {1} {2}} =$

We rewrite the terms in an equivalent way:

$5 ^ {\frac {2} {6}} * 2 ^ {\frac {3} {6}} =$

We rewrite the expression using the property mentioned:

$\sqrt [6] {5 ^ 2} * \sqrt [6] {2 ^ 3} =$

We combine using the product rule for radicals:

$\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}$

So:

$\sqrt [6] {5 ^ 2 * 2 ^ 3} =\\\sqrt [6] {25 * 8} =\\\sqrt[6]{200}$

ANswer:

Option b

4 0

2 years ago