Given: marked, PQ=8 PR=2x, TU=2z+3, ST=5z Find: PR and ST
1 answer:
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Answer:
Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable
Step-by-step explanation:
We are given the Function
f(x) =
The two basic hypothesis of the mean valued theorem are
- The function should be continuous in [0,2]
- The function should be differentiable in (1,2)
upon checking the condition stated above on the given function
f(x) is continuous in the interval [0,2] as the functions is quadratic and we can conclude that from its graph
also the f(x) is differentiable in (0,2)
f'(x) = 6x - 2
Now the function satisfies both the conditions
so applying MVT
6x-2 = f(2) - f(0) / 2-0
6x-2 = 9 - 1 /2
6x-2 = 4
6x=6
x=1
so this is the tangent line for this given function.
Answer:
60 tickets for children were sold
Step-by-step explanation:
Let x be the number of sold children's tickets and let y be the number of adult tickets sold, then we can pose the following equations.
(i) Because 132 tickets were sold in total
(ii) because the total of $ obtained by sales was 931.20.
We must clear x. Then we substitute (i) in (ii)
60 tickets for children were sold