Answer:
Component Form: v = <-1,6>
Magnitude of v: ||v|| = √37
Direction of v: θv = 100° (to the nearest degree)
Step-by-step explanation:
Component Form: v = <(5-6),(3-(-3))> = <-1,6>
Magnitude of v: ||v|| = √[(-1)²+(6)²] = √(1+36) = √37
Direction of v: α = tan⁻¹|6/-1| = tan⁻¹|-6| = tan⁻¹(6) = 80.53° which is your reference angle, but to verify that the angle is in the second quadrant, you'll need to do θv = 180° - 80.53° = 99.47°, therefore your direction angle is θv=100° to the nearest degree.
I can’t see it well...like it’s blurring
Answer:
tan∠E=1/3
Step-by-step explanation:
Tangent or opposite/adjacent of angle E is segment HF/3 to solve for HF you can use sine of H opposite over hypotenuse or √8/HF=sin45°. Rearranging the equation you get √8/sin45°=HF and sin45°= 2√2 so √8/2√2=1 HF=1 now you know that tan(∠E)=1/3.
Explanation: This is a linear equation because it's written in slope-intercept form or <em>y = mx + b</em> where the multiplier or the coefficient of the x-term represents the slope of the line and the<em> b</em> represents the constant term.
So the slope will be the coefficient of the <em>x-term</em> which means the number that is in front of the <em>x</em> which in this case is -5/4.
The y-intercept is the constant term which is +8