Answer:
$73.60
$345
simple interest = amount deposited x time x interest rate
600 + (600 x 0.055 x 5) = $765
600 + (600 x 0.055 x 5) > $2000
$765 $2000
He would not have $2000 in 5 years
Step-by-step explanation:
Total cost of items purchased = $75 + (2 x $8.50) = 92
If there is a 20% discount, he would pay (100 - 20%) 80% of the total cost =
0.8 x $92 = $73.60
commission earned = percentage commission x amount of sales
10% x $3450
= 0.1 x 3450 = 345
Amount he would have in his account = amount deposited + simple interest
simple interest = amount deposited x time x interest rate
600 x 0.055 x 5 = $165
Amount in his account in 5 years = $165 + 600 = $765
He would have less than $2000 in his account. he would have $765
1000 + 50x = 500 + 75x
First move 500 by subtracting it from 1000.
500 + 50x = 75x
Now subtract 50x from 75x.
500 = 25x
Then divide 500 by 25.
20 = x
They would've saved the same amount($2,000) on the 20th week.
The function is L = 10m + 50
Here, we want to find out which of the functions is required to determine the number of lunches L prepared after m minutes
In the question, we already had 50 lunches prepared
We also know that he prepares 10 lunches in one minute
So after A-lunch begins, the number of lunches prepared will be 10 * m = 10m
Adding this to the 50 on ground, then we have the total L lunches
Mathematically, that would be;
L = 10m + 50
Answer:
X=11
m<wxz= 23
Step-by-step explanation:
hope this helps branliest please