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1 year ago

5

Solve for x. Round your answer to the nearest tenth.

1 answer:

zlopas [31]1 year ago

7 0

Answer:

By Pythagorean theorem:

$c^2=a^2+b^2$

$x=\sqrt{15^2+33^2}$

$x=36.25$

$x=36.3$

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Korvikt [17]

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2 years ago

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Andrea's dad is 57 kilograms heavier than Andrea. Andrea weighs 34 kilograms. how much does Andrea's dad weigh?

lys-0071 [83]

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2 years ago

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3x ^2 - 9 x y ^2+ 12 X ^3Y^2

shepuryov [24]

$\huge \boxed{\mathfrak{Question} \downarrow}$

$3 x ^ { 2 } y - 9 x y ^ { 2 } + 12 x ^ { 3 } y ^ { 2 }$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$3 x ^ { 2 } y - 9 x y ^ { 2 } + 12 x ^ { 3 } y ^ { 2 }$

Factor out $3$ .

$3\left(x^{2}y-3xy^{2}+4x^{3}y^{2}\right)$

Consider $x^{2}y-3xy^{2}+4x^{3}y^{2}$ . Factor out $xy$ .

$xy\left(x-3y+4x^{2}y\right)$

Rewrite the complete factored expression.

$\boxed{ \boxed{ \bf \: 3xy\left(x-3y+4x^{2}y\right) }}$

4 0

2 years ago

Williiam lost 25% of his marble,gave 1/6 of the remainder to his.Brother and had 120 marbles left.How many marbles did he have a

bija089 [108]

Answer:

Number of marbles with Williams at the starting = 192

Step-by-step explanation:

Let total number of marbles with Williams = m

He lost marbles = 25% of the total number

= $\frac{25}{100}\times m$

= $\frac{m}{4}$

Remaining marbles with Williams = m - $\frac{m}{4}$

= $\frac{3m}{4}$

He gave marbles to his brother = $\frac{1}{6}$ th of the remaining marbles

= $\frac{1}{6}\times \frac{3m}{4}$

= $\frac{m}{8}$

Remaining marbles after giving marbles to his brother = 120

Therefore, $\frac{3m}{4}-\frac{m}{8}=120$

$\frac{6m}{8}-\frac{m}{8}=120$

$\frac{5m}{8}=120$

m = $\frac{120\times 8}{5}$

m = 192

Number of marbles with Williams at the starting = 192

5 0

2 years ago

he Carson family will purchase three used cars. There are two models of cars available, Model A and Model B, each of which is av

beks73 [17]

Answer:

Total number of combination = 32

Step-by-step explanation:

Given:

Number of cars = 3

Number of models = 2.

Number of color = 4

Find:

Total number of combination

Computation:

Total number of combination = [2³ x (2x3) x 4] / !3

Total number of combination = 32

7 0

2 years ago