The task is to show that the right side of the equation has units of [Time], just like the left side has.
The right side of the equation is . . . 2 π √(L/G) .
We can completely ignore the 2π since it has no units at all, so it has no effect on the units of the right side of the equation. Now the task is simply to find the units of √(L/G) .
L . . . meters
G . . . meters/sec²
(L/G) = (meters) / (meters/sec²)
(L/G) = (meters) · (sec²/meters)
(L/G) = (meters · sec²) / (meters)
(L/G) = sec²
So √(L/G) = seconds = [Time]
THAT's what we were hoping to prove, and we did it !
Answer:
76.4m/s
Explanation:
Given parameter:
Time taken = 7.8sec
Unknown:
Speed after it dropped = ?
Solution:
To solve this problem, we use one of the kinematics equation:
V = U + gt
V is the final speed
U is the initial speed = 0m/s
g is the acceleration due to gravity
t is the time taken
V = 0 + 9.8 x 7.8 = 76.4m/s
An element can be identified by its unique atomic number. When we look in the periodic table, we find that the element with an atomic number of 9292 is uranium. There is only option containing uranium which also confirms the mass number we found. So, the daughter nucleus of the decay is 234^U.
In an alpha decay, a positively charged particle similar to a helium-4 nucleus gets released from the parent nucleus spontaneously. As the composition suggests, an alpha particle consists of two protons and 2 neutrons. The particle does not travel much, but in short range, it carries the most energy.
It's smart to use the thermal energy provided by the radioactive decay to generate electricity. This allows for a stable supply of power without consuming much space which means the saved space can be used for more scientific equipment. The alpha particle, structurally equivalent to the nucleus of a helium atom.
Learn more about nucleus here:
brainly.com/question/23366064
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Answer:
Explanation:
Given
Weight of person
At highest point Magnitude of the normal force
net force at highest point
where centripetal force
Normal Force
Negative sign shows force is in upward direction
At bottom point centripetal force is towards the bottom