Ask question

Ask question

All categories

2 years ago

10

Select the correct answer from each drop-down menu. The general form of the equation of a circle is 7x2 + 7y2 − 28x + 42y − 35 =

0.

1 answer:

nignag [31]2 years ago

7 0

The general form of the equation of a circle is,

x² + y² + Dx + Ey + F = 0, where D, E, F are constants.

The given equation is 7x² + 7y² − 28x + 42y − 35 = 0. So, to convert this equation into a general form we just need to get rid of the leading coefficient 7.

Hence, divide both sides of the equation by 7. So,

$\frac{7x^2+ 7y^2-28x + 42y-35}{7} =0$

x² + y² − 4x + 6y − 5=0.

So, the general form of the equation is x² + y² − 4x + 6y − 5=0.

You might be interested in

how do graphs of y=1/x and y=5/(x+6) compare? I know the second graph shifts to left by 6 units but does it move down and how ma

yawa3891 [41]

<span>By multiplying the first function with number 5, the graph will stretch by the order of five, meaning that in the second graph every value of the x will correspond to the 5 times bigger value of y than in the first case. Due to the +6 component, the second graph shifts to the left by 6 units.</span>

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=The%20%5C%3A%20%20value%20%20%5C%3A%20of%20%20%5C%3A%20%20%5Csqrt%7B6%20%2B%20%20%5Csqrt%7B6%2

saul85 [17]

$\large\underline{\sf{Solution-}}$

<u>Let us assume that:</u>

$\sf \longmapsto x = \sqrt{6 + \sqrt{6 + \sqrt{6 + ... \infty } } }$

We can also write it as:

$\sf \longmapsto x = \sqrt{6 + x }$

Squaring both sides, we get:

$\sf \longmapsto {x}^{2} =6 + x$

$\sf \longmapsto {x}^{2} - x - 6 =0$

By splitting the middle term:

$\sf \longmapsto {x}^{2} - 3x + 2x - 6 =0$

$\sf \longmapsto x(x - 3) + 2(x - 3 ) =0$

$\sf \longmapsto (x+ 2)(x - 3 ) =0$

<u>Therefore:</u>

$\longmapsto\begin{cases} \sf (x+ 2) =0 \\ \sf (x - 3) = 0 \end{cases}$

$\sf \longmapsto x = - 2,3$

<u>But x cannot be negative. </u>

$\sf \longmapsto x = 3$

Therefore, the value of the expression is 3.

$\large\underline{\sf{Verification-}}$

Given:

$\sf\longmapsto x=3$

We can also write it as:

$\sf\longmapsto x = \sqrt{9}$

$\sf\longmapsto x = \sqrt{6+3}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{9}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+3}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{9}}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+3}}}$

This pattern will continue.

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+...\infty}}}$

7 0

2 years ago

Someone please help me will give BRAILIEST!!!!

Semenov [28]

That is dependent because it is changing.independent stays the same

7 0

2 years ago

Read 2 more answers

Which physical feature is shown?

alukav5142 [94]

Answer:

APPALACHIAN MOUNTAINS

HAVE A BEAUTIFUL DAY

PLEASE MARK THIS ANSWER AS THE BRAINLIEST

6 0

2 years ago

Definition: The _________ of a matrix is usually written as "m x n", where m is the number of rows and n is the number of column

n200080 [17]

Answer:

m

Step-by-step explanation:

6 0

2 years ago