Question

What value of x is in the solution set of 4x – 12 ≤ 16 + 8x?

Answer 1

Answer:

x = The set of real numbers greater than or equal to -7

Step-by-step explanation:

Given:

4x - 12 ≤ 16 + 8x

Here we need to solve for x.

Isolate the variables and constant terms

Subtract 4x on both sides, we get

4x - 4x - 12 ≤ 16 + 8x - 4x

-12≤ 16 + 4x

Now subtract 16 on both sides, we get

-12 - 16 ≤ 16 -16 + 4x

-28 ≤ 4x

This can be written as

4x ≥ -28

Divide both sides by 4, we get

x ≥ -28/4

x ≥ - 7

x = The set of real numbers greater than or equal to -7

Answer 2

The solution for the x-value in this set is -7≤x