Lets name the shortest piece a, the medium b and the longest c
Together they are 90inches
The longest is 30 inches longer than the shortest
The third piece is half the lenght of the longest
So if you place c=a+30 in the other 2 equasions you get
And
Now if you put this 2 toghether u get
Multyplied by 2
Meaning that a=18inches
Now that we have the lenght of a we put it in the previous equasion
So b=48/2 which means b=24inches
And together they must be 90 so
C=48inches
2,050,000 = 40,000 * a
a = 2,050,000 / 40,000 = 51.25 m/s^2
Answer:
y=2x+5
Step-by-step explanation:
At 0, you sit at 5 dollars. The Y axis is money spent, and the X axis is hours parked.
Answer:
116,200 km
Step-by-step explanation:
Here we have 2 cars, each one with it's corresponding costs. Let's write each cost as functions. The SUV costs $27,070 plus $0.018 per mile. Let x be the miles and SUV (x) the SUV's cost:
SUV(x)=27070+0.18x
We can do the same for the hybrid with a cost function H(x):
H(x)=32880+0.13x
We now need the cost of the SUV to be greater than the hybrid. This is SUV (x)> H(x):
27070+0.18x > 32880+0.13x
Let's subtract 27070 in each side:
0.18 x > 32880 - 27070 + 0.13x
Now let's subtract 0.13x in both sides:
0.05x > 5810
Divide both by 0.05:
x > 5810/0.05
x > 116,200
So, after 116,200km the SUV will turn to be more expensive.