Why doesnt a ball roll on forever after being kicked at a soccer game

1 answer:

7 0

Because, gravity and friction, gravity will pull ball down and friction gonna slow down ball. Also wind resistance and probably a lot of more, like geometry of ball.

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I need the answer please help

timurjin [86]

Answer:

A) Inertia

Explanation:

Inertia is why objects tend to resist changes in their motion. Like a rolling ball will keep rolling unless we try to add friction to it, which then would stop the ball.

3 0

1 year ago

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Two points are given in polar coordinates by : (r, θ) = (2.60 m, 50.0°)

alukav5142 [94]

Answer:

The distance between the 2 points is 4.6558 meters.

Explanation:

The distance between 2 points $(r_1,\theta _1),(r_2,\theta _2)$ is given by

$d=\sqrt{r_{1}^{2}+r_{2}^{2}-2r_1\cdot r_2cos(\theta _2-\theta _1)}$

In our case the given 2 points are $(2.60,50.0^{o}),(3.60,-46.0^{o})$ hence the distance is

$d=\sqrt{2.60^{2}+3.60^{2}-2\cdot 2.60\cdot 3.60\cdot cos(-46.0-50)}\\\\\therefore d=4.6558m$

5 0

2 years ago

An object has a kinetic energy ke, and potential energy pe. it also has a rest energy e0. what is the object's total energy e?

Dmitriy789 [7]

Look that one up in you text book PG:678 that is if you got the same book as my friend<span />

7 0

2 years ago

HELP!!! ASP EASY QUESTION! WILL GIVE BRAINEST IF U ANSWER!

Harlamova29_29 [7]

I believe the answer is Anther.
The Anther produces the pollen

5 0

2 years ago

g An electron enters a region of space containing a uniform 1.63 × 10 − 5 T magnetic field. Its speed is 121 m/s and it enters p

kolbaska11 [484]

Answer:

i. The radius 'r' of the electron's path is 4.23 × $10^{-5}$ m.

ii. The frequency 'f' of the motion is 455.44 KHz.

Explanation:

The radius 'r' of the electron's path is called a gyroradius. Gyroradius is the radius of the circular motion of a charged particle in the presence of a uniform magnetic field.

r = $\frac{mv}{qB}$

Where: B is the strength magnetic field, q is the charge, v is its velocity and m is the mass of the particle.

From the question, B = 1.63 × $10^{-5}$ T, v = 121 m/s, Θ = $90^{0}$ (since it enters perpendicularly to the field), q = e = 1.6 × $10^{-19}$ C and m = 9.11 × $10^{-31}$ Kg.