The larger the mass the mass and the speed, the larger the force it would produce if it crashes something. Some car crashes produce minor injuries because maybe this car is small and runs at very slow speed which would mean less force when in impact with another. However, if a big truck crashes, it is expected to produce a larger force causing catastrophic injuries.
Answer:
2683.3N
Explanation:
According to coulombs law which states that "the force of attraction existing between two charge q1 and q2 is directly proportional to the product of the charges and inversely proportional to the square of the distance (d) between them. Mathematically |F|= k|q1| |q2| /d² where;
F is the force of attraction between the charges
q1 and q2 are the charges
d is the distance between them
k is the coulombs constant
Given |q1|= 38.9 × 10^-6C and |q2| = 27.6399×10^-6C d = 6cm = 0.06m
k = 8.98755 × 109 Nm² /C²
Substituting the given data's in the equation we have;
|F| = 8.98755 × 10^9×38.9×10^-6×27.6399×10^-6/0.06²
|F| = 9.66/0.06²
|F| = 9.66/0.0036
|F| = 2683.3N
The magnitude of the force will be 2683.3N
Note that the modulus of the charges changes negative value of q2 to positive value. The opposite signs of the charges doesn't affect the final calculation, it only tells the force of attraction or repulsion between the charges. Since they are unlike charges, they will attract each other in the field.
All of the forces listed are correct. There are 4 presently known forces.
Second question os B. the Lorentz force. It's given by
F=q(E+VxB) where q is the electric charge, E is the electric field, V is the particle's velocity vector, B is the magnetic flux density, and "x" represents the vector cross product.
What are the options as the question would make a lot more sense?