The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
We have
3 / (x-5) - x/5
We make the GCF and we have
15/[ 5(x-5) ] - x(x-5)/[ 5(x-5)]
= [ 15 - x(x-5) ] [5(x-5)]
= [ 15 - x^2 + 5x] / [ 5 (x-5) ]
= [15 - x^2 + 5x]/[5x - 25]
An answer to your question is (15-x^2+5x)/(5x-25)
Answer is 40. A triangle equals 180 so all you do is subtract 65 and 75 from 180 to get your answer.
As a percent is out of 100% or 1 (as a whole number), the best thing to do is multiply it by ten, until you get a whole number. As you cannot have a decimal in a percentage. 2.45x10= 24.5. This is still a decimal, so you need to multiply it be ten again, 24.5x10= 245.
Therefore, 2.45 is a percent is 245%
Answer:
2/3
Step-by-step explanation:
f(x)=g(x)
-3x+4=2
Add 3x
3x+2=4
subtract 2
3x=2
divide by 3
x=2/3
