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2 years ago

The model represents x2 - 9x + 14 Which is a factor of x2 - 9x + 14? OX-9 OX-2 X+5

Mathematics

2 answers:

Vlad1618 [11]2 years ago

8 0

Answer:

x - 2

Step-by-step explanation:

The expression can be factored using the factors of 14, 2 and 7, which add to give 9.

x² -9x +14 = (x -2)(x -7)

One of the factors is (x -2).

Alexxandr [17]2 years ago

7 0

Answer:

x - 2

Step-by-step explanation:

To factorise the quadratic

Consider the factors of the constant term (+ 14) which sum to give the coefficient of the x- term (- 9)

The factors are - 7 and - 2, since

- 7 × - 2 = + 14 and - 7 - 2 = - 9, thus

x² - 9x + 14 = (x - 7)(x - 2) ← in factored form

Thus (x - 2) is a factor of the expression

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If varies inversely as . It is known that = 10 when = 3, find the value of when = 5.

Leto [7]

Answer:

y = 6

Step-by-step explanation:

If x varies inversely proportional as y.

$x=\dfrac{k}{y}$ , k is constant of proportionality

k = xy

When x = 3 and y = 10

k = 3×10

k = 30

Put x = 5,

$y=\dfrac{k}{x}\\\\y=\dfrac{30}{5}\\\\y=6$

So, the value of y is 6 when x is 5.

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2 years ago

Angle $eab$ is a right angle, and $be = 9$ units. what is the number of square units in the sum of the areas of the two squares

Alla [95]

Let the measure of side AB be x, then, the measue of side AE is given by

$AE=\sqrt{9^2-x^2}$ .

Now, ABCD is a square of size x, thus the area of square ABCD is given by

$Area=x^2$

Also, AEFG is a square of size $\sqrt{9^2-x^2}$ , thus, the area of square AEFG is given by

$Area=\left(\sqrt{9^2-x^2}\right)^2=9^2-x^2=81-x^2$

<span>The sum of the areas of the two squares ABCD and AEFG is given by

$x^2+81-x^2=81$

Therefore, </span>the number of square units in the sum of the areas of the two squares <span>ABCD and AEFG is 81 square units.</span>

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2 years ago

What’s is the answer

kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

$(x^{2} )^{3} = x^6$

$(x^{3} )^5=x^{15}$

When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

$(x^{2} )(x^{3})=x^{5}$

$(x^{1} )(x^{2})=x^{3}$

$(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}$

You multiply 3 into each exponent in the numerator and the denominator

$\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

$\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}$

When you have something like this:

$\frac{x^{2}}{x^5}$

You subtract the exponents together, so:

$\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}$

Your answer is the second option

3 0

2 years ago

I need help on 10,11,12, and 13 plz help me

Mila [183]

10. 14
2 * 7 <==

11. 12
6 * 2
2 * 3 * 2 = 2^2 * 3 <==

12. 15
3 * 5 <==

13. ur gonna have 3 tables that each have 4 chairs

7 0

2 years ago

A student has passed 60 percent of the 20 quizzes he has written so far successfully. If the student writes 50 quizzes during th

NikAS [45]

60% of 20 quizzes = 60/100*20 quizzes = 12 quizzes

Amount of quizzes remaining = 50 quizzes - 20 quizzes = 30 quizzes

He passes 80% of those 30 quizzes, so

80/100 * 30 quizzes = 24 quizzes

So, he passed 12 quizzes from the initial bunch and 24 quizzes from the rest, which totals to 12 quizzes + 24 quizzes = 36 quizzes.

Then, you see that he passed 36 quizzes, out of the total 50 quizzes, so the ratio is 36 quizzes / 50 quizzes = 36/50, which when converted as a percentage is 36/50 * 100% = 72%.

Therefore, he passed 72% of the quizzes for the entire year.

4 0

2 years ago