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3 years ago

Help Please(pre algebra)

Mathematics

1 answer:

miv72 [106K]3 years ago

7 0

Where’s the problem?

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In the data set below, what is the interquartile range? 7 1 5 5 9 Submit

Marizza181 [45]

Answer:

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile.

First find the median.

The median is the middle value of the data set arranged in ascending order

1 5 5 7 9 ← data in ascending order

↑ median

The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.

1 5

↑ lower quartile = $\frac{1+5}{2}$ = 3

The upper quartile is the middle value of the data to the right of the median.

7 9

↑ upper quartile = $\frac{7+9}{2}$ = 8

Thus

interquartile range = 8 - 3 = 5

3 0

2 years ago

If a =-2 and b= 2 what will be the value of a^b

raketka [301]

Write out the equation;

y=a^b
y=(-2)^2
y=(-2)(-2)
y=4

Therefore, the value of a^b is 4

Hope I helped :)

7 0

2 years ago

Read 2 more answers

Simplify: Cube root of (128a^13b^6)

Pavlova-9 [17]

$\sqrt[3]{128a^{13}b^{6}} \\\sqrt[3]{64a^{12}b^{6} * 2a} \\\sqrt[3]{64a^{12}b^{6}}\sqrt[3]{2a} \\4a^{4}b^{2}\sqrt[3]{2a}$

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2 years ago

Randy hung a total of 900 feet of Christmas lights on the exterior of his house this past holiday season. If 1 foot equals 30.48

motikmotik

I’m trying to work it out right now but either way search it up it might come out

7 0

2 years ago

Help this is due tomorrow

Helen [10]

-4.4(s - 2) + 6.9s = 14.8

Distribute -4.4 into the parenthesis:

-4.4s + 8.8 + 6.9s = 14.8

Combine like terms:
2.5s + 8.8 = 14.8

Subtract 8.8 from both sides of the equation:

2.5s + 8.8 - 8.8 = 14.8 - 8.8

2.5s = 6

Divide both sides by 2.5:

2.5s/2.5 = 6/2,5

s = 2.4

s =

6 0

2 years ago