Answer:
zero goats and 120 Ilamas to get profit of $15,120
Step-by-step explanation:
Goats: G
Ilamas: l
Explicit constraints:
2G + 5l ≤ 400
100G+ 80l≤ 13,200
Implicit constraints
G≥0
I≥0
P= 84G+ 126l
See attachment for optimal area
substituting coordinats of optimal region in profit equation to get profit
When G= 132, l=0
P=84(132) + 126(0)
P=11,088
When G=0, l=120
P=84(0)+ 126(120)
P = 15120
When G= 100, l=40
P=84(100)+126(40)
P=13440
Answer:
185
Step-by-step explanation:
Answer:
Okapi 290 kg
Llama 160 kg
Step-by-step explanation:
Let weight of each llama be
Let weight of each okapi be
<em>Given, combined weight of 1 okapi and 1 llama is 450, we can write:</em>
<em></em>
<em>Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:</em>
<em></em>
Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:
Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:
Each okapi weigh 290 kg
Answer:
1.95 * 10^7
Step-by-step explanation:
19.5 million
write in standard notation
19500000
convert to scientific notation (by making the number such that the largest digit is in the one's place)
1.95 * 10^7