Answer:
- see below for a drawing
- the area of one of the trapezoids is 20 units²
Step-by-step explanation:
No direction or other information about the desired parallelogram is given here, so we drew one arbitrarily. Likewise for the segment cutting it in half. It is convenient to have the bases of the trapezoids be the sides of the parallelogram that are 5 units apart.
The area of one trapezoid is ...
A = (1/2)(b1 +b2)h = (1/2)(3+5)·5 = 20 . . . . square units
The sum of the trapezoid base lengths is necessarily the length of the base of the parallelogram, so the area of the trapezoid is necessarily 1/2 the area of the parallelogram. (The area is necessarily half the area of the parallelogram also because the problem has us divide the parallelogram into two identical parts.)
We know that
in a right triangle
Applying the Pythagoras Theorem
c²=a²+b²
in this problem
c=√87 yd
a=√23 yd
b=?
so
b²=c²-a²-----> b²=(√87)²-(√23)²----> b²=87-23----> b²=64----> b=8 yd
the answer is
8 yd
The first step you should do is subtract 32 from both sides so your answer will turn out like this -
F = (9/5) C + 32
-
F - 32 = (9/5)
Then we will multiply both sides by 5.
5 ( F - 32 ) = 9 C
Divide both sides by 9 to isolate C.
(5/9) ( F - 32 ) = C
So the answer is :
C = (5/9) ( F - 32 )
Hope this helps :)
Answer:
=5/6
Step-by-step explanation:
happy to help ya :)
Answer:
$3.03
Step-by-step explanation:
7x + $3.60 = $24.81
Subtract $3.60 from both sides of the equation:
7x + $3.60 - $3.60 = $24.81 - $3.60
7x = $24.81 - $3.60
7x = $21.21
Divide each side by 7:
(7x/7) = ($21.21/7)
x = ($21.21/7)
x = $3.03