As,
CuCO₃ ⇆ Cu²⁺ + CO₃²⁻
So,
Kc = [Cu²⁺] [CO₃²⁻] / CuCO₃
Or,
Kc (CuCO₃) = [Cu²⁺] [CO₃²⁻]
Or,
Ksp = [Cu²⁺] [CO₃²⁻]
As,
Ksp = 1.4 × 10⁻¹⁰
So,
1.4 × 10⁻¹⁰ = [x] [x]
Or,
x² = 1.4 × 10⁻¹⁰
Or,
x = 1.18 × 10⁻⁵ mol/L
To cahnge ito g/L,
x = 1.18 × 10⁻⁵ mol/L × 123.526 g/mol
x = 1.45 × 10⁻³ g/L
Answer:
Explanation:
N and P will have similarity
Electronic configuration of N
2,5
1s²2s²p⁵
Electronic configuration of P
1s²2s²2p⁶3s²3p⁵
Electronic configuration bears similarity.
Both have 5 electrons in their outermost orbits . So they exhibit similarity in their properties. Both belong to the same 15 th group of periodic table.
Sr and Rb too bear much similarity . Both are strongly electro-positive metal , difference in their atomic no being only one.
Answer:
Explanation:
final temperature of the cube
initial temperature of the cube
mass of the cube
specific heat of aluminum