Feso3 compound name
Iron(II) Sulfite FeSO3 Molecular Weight
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Answer:
0.35 atm
Explanation:
To solve this problem, we use Boyle's Law: , where P is the pressure and V is the volume.
Here, V_1 = 0.355 L, P_1 = 1.0 atm, and V_2 = 0.125 L. So, just plug these values into the equation:
(1.0) * (0.355) = * (0.125) ⇒ ≈ 0.35 atm
Thus, the pressure is 0.35 atm.
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Answer:
No wind
Rain
I only came up with 2 I couldnt think of a third one
Answer:
Cac2 is a answer please mark me brainliest
n = 1.5atm (15L) / .0821 (280k) = .98 mol NaCl
NaCl = 22.99g Na + 35.45g Cl = 58.44g NaCl
58.44g NaCl x .98 mol NaCl = 57.27g NaCl
Explanation:
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