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2 years ago

Evaluate the following expression when a = -3, b = 2, c = 5, and d= -4. 4c + d

Mathematics

2 answers:

Delicious77 [7]2 years ago

8 0

Answer:

-24

Step-by-step explanation:

this is how I think it should be done

Solution:

4c+d

4×5(c)-4(d)

20+-4

=-24

Elan Coil [88]2 years ago

4 0

Answer:

Hello!!! Princess Sakura here ^^

Step-by-step explanation:

The first step you need to do is plug in the numbers...

$4(5)+(-4)$

Then you will distribute the positive 1 but that won't change much...

$4(5)-4$

Then you'll have to multiply the 4 and 5 to get....

$20 -4$

Now from here should be a piece cake, so the answer is...

$16\\$

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2 years ago

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In-s [12.5K]

Answer the answer is 25

Explanation:

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2 years ago

Suppose that v1(t)=100cos(ωt)and v2(t)=100sin(ωt). Use phasors to reduce the sum vs(t)=v1(t)+v2(t) to a single term of the form

GuDViN [60]

Answer:

$vs(t)=152.08cos(\omega t -45)=152.08\angle-45$

Step-by-step explanation:

A tension expressed in form:

$V(t)=Vm*cos(\omega t+\phi)$

It can be converted directly into a fasor:

$V(t)=Vm\angle \phi$

If the function is a positive sine we subtract 90 °

$V(t)=Vm*sin(\omega t+\phi)=Vm*cos(\omega t+\phi-90)$

So:

$v1(t)=100cos(\omega t)= 100\angle0\\v2(t)=100sin(\omega t)=100cos(\omega t-\ph90)=100\angle -90$

$vs(t)=v1(t)+v2(t)=100\angle 0 +100\angle-90=152.0811931\angle-45\approx152.08\angle-45$

Therefore:

$vs(t)=152.08\angle-45=152.08cos(\omega t -45)$

7 0

2 years ago

pickupchik [31]

Answer:

Step-by-step explanation:

31 + 371 + 21 = 423

31/423 = 7%

8 0

1 year ago

In question use, 1 kilogram= 2.2 pounds, 1 stone= 14 pounds change 42 kilograms into stones

Marina86 [1]

Answer:

6.6 stone

Step-by-step explanation:

We will use conversions to change kilograms to stones

1 kilogram= 2.2 pounds,

1 stone= 14 pounds

42 kilogram 2.2 lbs 1 stone

--------------- * ------------- * ---------------

1 kg 14 lbs

All the units cancel except stone

(42*2.2)/14 stone

6.6 stone

8 0

2 years ago

Read 2 more answers