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3 years ago

7

How do u insult someone who has been all but nice to you and you really wanna be their friend?

1 answer:

Makovka662 [10]3 years ago

4 0

Answer: you don't insult someone when they are being nice to you i i cant even do that c:

Step-by-step explanation:

You might be interested in

What operation does “the sum of 4 and 18” indicate?

skelet666 [1.2K]

Step-by-step explanation:

22 because if we add4+18=22

7 0

2 years ago

Read 2 more answers

Which expression is equivalent to 10- (2x^3 + 11x^2 - 2x - 35)

Semenov [28]

Answer:

22x^2+x+3

Step-by-step explanation:

5 0

2 years ago

4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

so

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

or

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

so

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

or

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

5 0

2 years ago

Hi, what is the answer to 4 • 7 – 62 ÷ 3

xeze [42]

Answer:

22/3

Step-by-step explanation:

$4\times\:7-\frac{62}{3}\\\\\mathrm{Multiply\:the\:numbers:}\:4\times\:7=28\\=28-\frac{62}{3}\\\\\mathrm{Convert\:element\:to\:fraction}:\quad \:28=\frac{28\times\:3}{3}\\=\frac{28\times\:3}{3}-\frac{62}{3}\\\\=\frac{28\times\:3-62}{3}\\\\28\times\:3-62=22\\\\=\frac{22}{3}$

8 0

2 years ago

Find the midpoint of the segment with the given endpoints.<br> (3,- 9) and (4, -8)

frez [133]

(3,-9)
(4,-8)

$\boxed{\sf (x,y)=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)}$

$\\ \sf\longmapsto \left(\dfrac{3+4}{2},\dfrac{-9+8}{2}\right)$

$\\ \sf\longmapsto \left(\dfrac{7}{2},\dfrac{-1}{2}\right)$

3 0

2 years ago