How does temperature influence a chemical change?

Two masses traveling at the same speed v₀ collide head on. Nothing is known about the collision other than that it is not comple

alex41 [277]

Answer:

false

Explanation:

Elastic collision: the collision is said to be elastic if the kinetic energy is conserved during the collision.

If the kinetic energy is not conserved, then the collision is not elastic.

So, here no information is given so we cant say about the type of collision.

So, it is False.

4 0

2 years ago

A series combination of two resistors, 7.25 ω and 4.03 ω, is connected to a 9.00 v battery.

almond37 [142]

a. $11.28\Omega$

The equivalent resistance of a series combination of two resistors is equal to the sum of the individual resistances:

$R_{eq}=R_1 + R_2$

In this circuit, we have

$R_1 = 7.25 \Omega\\R_2 = 4.03 \Omega$

Therefore, the equivalent resistance is

$R_{eq}=7.25 \Omega + 4.03 \Omega=11.28 \Omega$

b. 5.8 V, 3.2 V

First of all, we need to determine the current flowing through each resistor, which is given by Ohm's law:

$I=\frac{V}{R_{eq}}$

where V = 9.00 V and $R_{eq}=11.28 \Omega$ . Substituting,

$I=\frac{9.00 V}{11.28 \Omega}=0.8 A$

Now we can calculate the potential difference across each resistor by using Ohm's law again:

$V_1 = I R_1 = (0.8 A)(7.25 \Omega)=5.8 V$

$V_2 = I R_2 = (0.8 A)(4.03 \Omega)=3.2 V$

4 0

2 years ago

List 5 good insulators and 5 good conductors

damaskus [11]

Insulators- fur, plastic, lots of non metals
Conductors- metals, wire, most metals
:)

3 0

2 years ago

A 6.9-kg wheel with geometric radius m has radius of gyration computed about its mass center given by m. A massless bar at angle

Vilka [71]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is $\alpha =2.538 \ rad/s^2$

Explanation:

From the question we are told that

The mass of the wheel is m = 6.9 kg

The radius is $r = 0.69 \ m$

The radius of gyration is $k_G = 0.4\ m$

The angle is $\theta = 47^o$

The force which the massless bar is subjected to $F = 22.5 \ N$

Generally given that the wheels rolls without slipping on the flat stationary ground surface, it implies that point A is the center of rotation.

Generally the moment of inertia about A is mathematically represented as

$I_a = I_G + M* r^2$

Here $I_G$ is the moment of inertia about G with respect to the radius of gyration which is mathematically represented as

$I_G = M * k_G$

=> $I_a = k_G* M + M* r^2$

=> $I_a =0.4 * 6.9 + 6.9 * 0.69^2$

=> $I_a =6.045 \ kg \cdot m^2$

Generally the torque experienced by the wheel is mathematically represented as

$\tau = F * cos (47)$

=> $\tau = 22.5 * cos (47)$

=> $\tau = 15.34 \ kg \cdot m^2 \cdot s^{-2}$

Generally this torque is also mathematically represented as

$\tau = I_a * \alpha$

=> $15.34 = 6.045 * \alpha$

=> $\alpha =2.538 \ rad/s^2$

4 0

2 years ago

The density of aluminum is 2.70 g/ml. A piece of aluminum foil has a mass of 44 g. What is the volume of this piece of aluminum

anyanavicka [17]

Answer:

C) 16.3 ml

Explanation:

Density is equal to the ratio between the mass of an object and its volume:

$d=\frac{m}{V}$

where

m is the mass

V is the volume

In our problem, we know:

- density of aluminium: $d=2.70 g/mL$

- mass of the aluminium foil: $m=44 g$

So we can re-arrange the equation above and use these data to find the volume of the piece of aluminium foil:

$V=\frac{m}{d}=\frac{44 g}{2.70 g/mL}=16.3 mL$

7 0

3 years ago