Answer:
The magnetic field strength is 0.29 T.
Explanation:
Given that,
Length of current-carrying wire, L = 52 cm = 0.52 m
Current, I = 15 A
Magnetic force, F = 2.3 N
We need to find the magnetic field strength. We know that the magnetic force is given by :
B is magnetic field strength
So, the magnetic field strength is 0.29 T.
Answer:
(a) The average speed is 0.85 milles/minute
(b) The average velocity is zero
Explanation:
In order to answer part (a) and (b) you have to apply the formulas for average speed and average velocity which are:
<em>-Average speed formula:</em>
where d is the total distance traveled and t is the tota time
Replacing the given values:
milles/minute
Notice that you have to replace the total distance, which is 14 milles for the go plus 14 milles for the return. The same for the total time.
<em>-Average velocity formula:</em>
V = Δx/Δt
Where V is the velocity vector, Δx is the displacement and Δt is the change in time
V=
Where X2 is the final position and X1 is the initial position
In this case X1= 0 i and X2=0 i (i is the unit vector in the x direction). So, the displacement is zero.
Therefore, the average velocity is:
V= 0 i [milles/minute]
Answer:
Explanation:
The strength of the gravitational field at the surface of a planet is given by
(1)
where
G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
For the Earth:
For the unknown planet,
Substituting into the eq.(1), we find the gravitational acceleration of planet X relative to that of the Earth:
And substituting g = 9.8 m/s^2,
