Answer:
Atomic Mass: 78.96 amu. Melting Point: 217.0 °C (490.15 K, 422.6 °F) Boiling Point: 684.9 °C (958.05005 K, 1264.8201 °F) Number of Protons/Electrons: 34 ... [Bohr Model of Selenium] ... im sorry hope this helped
Explanation:
Answer:
The right answer is "![[Na^+]=5.57 \ ppm](https://tex.z-dn.net/?f=%5BNa%5E%2B%5D%3D5.57%20%5C%20ppm)
".
Explanation:
The given values are:
According to the question,
The concentration of standard will be:
= 
= 
= 
Coffee after dilution,
⇒ 
or,
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
hence,
In unknown sample, the concentration of coffee will be:
= 
= 
= 
I believe it is the second option
Answer:
It would take 3.11 J to warm 3.11 grams of gold
Explanation:
Step 1: Data given
Mass of gold = 3.11 grams
Temperature rise = 7.7 °C
Specific heat capacity of gold = 0.130 J/g°C
Step 2: Calculate the amount of energy
Q = m*c*ΔT
⇒ Q = the energy required (in Joules) = TO BE DETERMINED
⇒ m = the mass of gold = 3.11 grams
⇒ c = the specific heat of gold = 0.130 J/g°C
⇒ ΔT = The temperature rise = 7.7 °C
Q = 3.11 g * 0.130 J/g°C * 7.7 °C
Q = 3.11 J
It would take 3.11 J to warm 3.11 grams of gold
