Answer:
Explanation:
Hello,
In this case, it is widely known that for isochoric processes, the change in the enthalpy is computed by:
Whereas the change in the internal energy is computed by:
So we compute the initial and final temperatures for one mole of the ideal gas:
Next, the change in the internal energy, since the volume-constant specific heat could be assumed as ³/₂R:
Then, the volume-pressure product in Joules:
Finally, the change in the enthalpy for the process:
Best regards.
The mass of He gas = 21.428 g
<h3>Further explanation</h3>
Given
120 liters of He gas
Required
the mass in grams
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.
Mol for 120 L :
Mass of He gas(MW=4 g/mol) :
number of moles = 1.00 X 10^22 ÷ 6.022 × 10^23
= 0.0166 moles
mass = number of moles × molar mass
= 0.0166 × 120.37 = 2.00 g