Answer:
JADAAAAAA! I snuck on brainly while im at the library! get on rob lox!
Think the quality of it is based off of the amount of time some one worked on something. 2. If all of the data values in the class were compiled in a giant histogram, and a curve was drawn over the graph, where should the highest point on the curve occur? It should be were the mode is because there is the most of the mode in the data set. 3. What phase(s) of a design process might statistics be most applicable? The revising stage. 4. Other than dial calipers, what kinds of tools are used to precisely measure objects for purposes of quality control? A ruler/ measuring tape or you can use a scale and you could measure well.
Answer:
if, 1 + 3 - (8 * 334 * 123) = x
then, x = -328652
Answer: n = 75; p = 30
Explanation: (a) 5p + 4n = 450 where p is for pen and n is for notebook.
(b) 10p + 3n = 525
We can use the elimination method to solve these two equations.
1. Multiply the first equation by 2 so that 10p will cancel out:
2(5p + 4n = 450)
- 10p + 3p = 525
10p + 8n = 900
- 10 p + 3n = 525
5n = 375
2. Divide by 5 to get n alone: n = 75
3. Plug 75 into the first equation: 5p + 4(75) = 450
5p + 300 = 450
4. Subtract 300 from 450: 5p = 150
5. Divide by 5 to get p alone: p = 30
We can test if this is correct by plugging our answers into the second equation:
10(30) + 3(75) = 525
300 + 225 = 525
525 = 525
This is a true statement, which means that our answers are correct.
Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean total cholesterol level of all males.
Number of sample, n = 355
Mean, u = 185 mg
Standard deviation, s = 16
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
185 +/- 1.96 × 16/√355
= 185 +/- 1.96 × 0.849
= 185 +/- 1.66404
The lower end of the confidence interval is 185 - 1.66404 =183.336
The upper end of the confidence interval is 185 + 1.66404 = 186.66
Therefore, with 95% confidence interval, the mean total cholesterol level of all males is between 183.336 mg and 186.66 mg
