You think I know right? yeah so no way boy I'm so sorry not my intencion
Answer:
(s-6)/r
option D
Step-by-step explanation:
The slope-intercept form a line is y=mx+b where m is the slope and b is the y-intercept.
Compare y=mx+b and y=cx+6, we see that m=c and c is the slope.
Now we are also given that (r,s) is on our line which means s=c(r)+6.
We need to solve this for c to put c in terms of r and s as desired.
s=cr+6
Subtract 6 on both sides:
s-6=cr
Divide both sides by r:
(s-6)/r=c
The slope in terms of r and s is:
(s-6)/r.
1/5 is an expression that represents 1÷5= .2
Since the return decimal equivalent doesn't go on forever and has a finite end, this is a member of the rational number set.
Step-by-step explanation:
You're given that ΔUVW is similar to ΔYZW. The tricky part is identifying which sides in ΔUVW correspond to which sides in ΔYZW.
The triangles share point W, so visually rotate one triangle around W until the two triangles align. That way, you can see that UW and ZW correspond to each other, and VW and YW correspond to each other.
Now you can find the scale:
VW / YW = 5/12
And you can write a proportion to find x:
UW / ZW = VW / YW
x / 64 = 5 / 12
x = 26 ⅔
Answer:
Period ⇒ 40
Amplitude ⇒ 12
Mid-line ⇒ 32
Step-by-step explanation:
The table is counting by 4's and the period is the amount of space between 2 peaks. In this scenario, we can find the peaks by looking for two of the same highest value (44). We can see that x=40 has a value of 44 while the other is actually not shown because it would be located at x=0. Therefore the period is 40
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The amplitude can be found by using the following:
Our maximum is 44 and our minimum is 20.
The amplitude is 12
The amplitude is the distance from the peak to the mid-line. To find the mid-line, we can either subtract our amplitude from our maximum value (44) or add our amplitude to our minimum value (20)
44 - 12 = 32
20 + 12 = 32
Therefore our mid-line is y = 32
~Hope this helps!~
