Y < 4x - 2......u have a slope of 4.....u have a y int (where the line crosses the y axis) at (0,-2)......and u have a < sign....meaning it is a dashed line shaded below the line
and if u want to find ur x int (where the line crosses the x axis) sub in 0 for y and solve for x...disregarding the inequality sign y = 4x - 2 0 = 4x - 2 -4x = -2 x = -2/-4 x = 1/2.....so ur line crosses the x axis at (1/2,0)
so ur graph is : graph 3 ======================== y > -x + 3.....u have a slope of -1....u have a y int at (0,3)....ur inequality sign is >....meaning it is a dashed line, because there is no equal sign...and it is shaded above the line since it is greater then
ur x int is : y = -x + 3 0 = -x + 3 x = 3......x int at (3,0)
ok..I am having a problem with this one because none of ur graphs match this inequality...because ur line will cross the x axis at 3...and none of ur graphs show this =================== y < -2......when u have y = a number (or <,>) this will be a horizontal line....it will go thru -2 all the way across....and since it has a < sign, it will be a dashed line with shading under the line. so ur graph is : graph 2
Since both variable are the same, you can divide the numbers. 27/3=9. Add back in the variable, and the answer would be 9h. That's how I would solve it at least
