Answer:
1-8
Step-by-step explanation:
I was only able to finish one through eight The rest follow the same concept though
Answer:
y-axis is x = 0
Step-by-step explanation:
if P(x, y) is any point on AB, then x = a. Hence, the equation of a straight line parallel to the y-axis at a distance from it is x = a. The equation of the y-axis is x = 0, since, the y-axis is parallel to itself at a distance 0 from it.
The eccentricity of an eclipse is found by using the
formula, eccentricity = c/a
Where,
c represents the distance between the center and a focus.
a represent the distance between that focus and a vertex
The numerical value of the eccentricity of an eclipse ranges
between 0 and 1
Answer:
187 ft/s
Step-by-step explanation:
Given in the y direction:
v₀ = 0 ft/s
Δy = 75 ft
a = 32 ft/s²
Find: t
Δy = v₀ t + ½ at²
(75 ft) = (0 ft/s) t + ½ (32 ft/s²) t²
t = 2.165 s
Given in the x direction:
Δx = 480 ft
a = 0 ft/s²
t = 2.165 s
Find: v₀
Δx = v₀ t + ½ at²
(480 ft) = v₀ (2.165 s) + ½ (32 ft/s²) (2.165 s)²
v₀ = 187 ft/s
Its simple, the expression is 7+x and it does not have an equal sign since it is not an equation
