Question

A sample of 8.11 g 8.11 g of solid calcium hydroxide is added to 38.0 mL 38.0 mL of 0.410 M 0.410 M aqueous hydrochloric acid. Write the balanced chemical equation for the reaction. Physical states are optional. chemical equation:

Answer 1

Answer:

The balanced chemical equation :

$Ca(OH)_2(s)+2HCl(aq)\rightarrow CaCl_2(aq)+2H_2O(l)$

Explanation:

When calcium hydroxide reacts with hydrochloric acid it gives calcium chloride and water as a products. The chemical equation is given as:

$Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O$

According to question, solid calcium hydroxde is added to 38.0 mL of 0.410 M of HCl solution, so the chemical equation can be written as:

$Ca(OH)_2(s)+2HCl(aq)\rightarrow CaCl_2(aq)+2H_2O(l)$

According to stoichiometry, when 1 mole of solid calcium hydroxide reacts with 1 mole of hydrochloric acid to gives 1 mole of aqueous calcium chloride and 1 mole of water.