Answer:
5.645 × 10⁻²³ g
Solution:
Step 1) Calculate Molar Mass of SH₂;
Atomic Mass of Sulfur = 32 g/mol
Atomic Mass of H₂ = 2 g/mol
--------------------
Molecular Mass of SH₂ = 34 g/mol
Step 2: Calculate mass of one molecule of SH₂ as;
As,
Moles = # of Molecules / 6.022 × 10²³
Also, Moles = Mass / M.Mass So,
Mass/M.mass = # of Molecules / 6.022 × 10²³
Solving for Mass,
Mass = # of Molecules × M.mass / 6.022 × 10²³
Putting values,
Mass = (1 Molecule × 34 g.mol⁻¹) ÷ 6.022 × 10²³
Mass = 5.645 × 10⁻²³ g
<span>4 I</span>₂<span>+ 9 O</span>₂<span> = 2 I</span>₄<span>O</span>₉
Reactants :
I₂ , O₂
Products :
I₄O₉
hope this helps!
Answer:
0.5059kg
Explanation:
The heat absorbed for the water is determined using the equation:7
Q = C×m×ΔT
<em>Where Q is heat absorbed (4300cal)</em>
<em>C is specific heat (1cal/g°C)</em>
<em>m is the mass in grams</em>
<em>ΔT is change in °C (101.0°C - 92.5°C = 8.5°C)</em>
<em />
Replacing:
4300cal = 1cal/g°C×m×8.5°C
505.9g = m
In kg, the mass of water is:
<h3>0.5059kg</h3>
<em />
Let's note that 1 pint = 473.1765 mL, so 11 pints should be 5204.9415 mL.
We make a proportion out of the word problem
(85 mg glucose/ 100 mL) times (1 g/ 1000 mg) = 4.4242 grams of glucose
Hello!
The balanced equation for the
neutralization of KOH is the following:
HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)
To calculate the
volume of HCl required, we can apply the following equation:
So, the required volume of HCl is
541,54 mLHave a nice day!
