Answer is: A) 124 s.
c₀ = 3 mol/L.
c₁ = 0,700 mol/L.
k = 8,8·10⁻³ 1/M·s.
Integrated second order rate law is: 1/c₁ = 1/c₀ + k·t.
k·t = 1/0,700 - 1/3.
0,0088·t = 1,095.
t = 1,095 ÷ 0,0088.
t = 124 s.
c₀ - <span>initial concentration.
c</span>₁ - <span> concentration at a particular time.
k - </span><span>the rate constant.
t - time.</span>
Explanation:
It is given that vapor pressure of liquid iodomethane is 40.0 mm Hg. So, if we calculate the vapor pressure according to the given values and if its value will be greater than the the given vapor pressure of iodomethane then it means that some of the vapors has converted into liquid state.
As the given values are as follows.
= 72.0 mm Hg, = 404 K
= ? , = 249 K
As volume is constant so, according to Gay-Lussac's law pressure is directly proportional to temperature.
(at constant volume)
or, = k
Therefore, the formula to calculate the value of is as follows.
=
=
= 44.37 mm Hg
As calculated vapor pressure is more than the given vapor pressure. Hence, the liquid will convert into gas.
As a result, no condensation will occur and only vapors of iodomethane will be present.
Answer:
from the ideal gas law, P2 /P1 = T2 /T1 for the same volume and quantity of gas. P2 = (758 mmHg) (45 +273 K) / (15 +273K) = 837 mmHg.
Explanation:
They are known as “American Central”
The tool to measure the liquid is a measuring cylinder.