The by-product of the chlorination of an alkane is <u>HCl</u>
Explanation:
- Chlorination is the process of adding chlorine to drinking water to disinfect it and kill germs. Different processes can be used to achieve safe levels of chlorine in drinking water.
- Chlorination of alkane gives a mixture of different products.
- When consider mechanism of alkanes chlorination, free radicals are formed during the reaction to keep the continuous reaction.
- Different alkyl chloride compounds, extended carbon chains compounds and HCl are formed as products in product mixture.
- Chlorination byproducts, their toxicodynamics and removal from drinking water.
- Halogenated trihalomethanes (THMs) and haloacetic acids (HAAs) are two major classes of disinfection byproducts (DBPs) commonly found in waters disinfected with chlorine
- Chlorine is available as compressed elemental gas, sodium hypochlorite solution (NaOCl) or solid calcium hypochlorite (Ca(OCl)2
Answer:
0.143L
Explanation:
Molar mass of H2SO4 = 98g/Mol
No of mole = mass/molar mass
No of mole= 49/98 = 0.5 mol
No of mol = concentration × volume
Volume = n/C = 0.5/3.5 = 0.143L
The correct Answer is A.
The Flow chart of the Carbon Cycle, will look as follows:
1. Carbon dioxide in the atmosphere.
2. Producers undergo photosynthesis (in this process plants among other producers like algae, use CO2 to produce energy).
3. Consumers eat producers (a primary level of consumer like a rabbit eats the producers or plants).
4. Decomposers return Carbon to the soil and release waste.
And the cycle continues again, by going back to step 1.
Answer:
5.46 8 x 10²³ molecules.
Explanation:
- <em>Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³).</em>
<em><u>Using cross multiplication:</u></em>
1.0 mole → 6.022 x 10²³ molecules.
9.08 x 10⁻¹ mole → ??? molecules.
∴ The no. of molecules of CO₂ are in 9.08 x 10⁻¹ mol = (6.022 x 10²³ molecules) ( 9.08 x 10⁻¹ mole) / (1.0 mol) = 5.46 8 x 10²³ molecules.
