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2 years ago

After a projectile is fired into the air, what is the acceleration in the x-direction? (Assume no air resistance.)

Physics

2 answers:

storchak [24]2 years ago

5 0

Answer:

$a_x = 0$

Explanation:

When projectile is in air then the force on the projectile is only due to its weight

It is vertically downwards

$F_g = mg(-\hat j)$

so here since we don't have any air drag or friction due to air so there will be no force along its tangent or along x direction

so the acceleration along x direction will be zero

$a_x = 0$

$a_y = - g$

Gre4nikov [31]2 years ago

4 0

Without air resistance, there is no horizontal force on the projectile,
so it has no horizontal acceleration. The answer is "zero".

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Explanation:

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Please help me with this question :

aalyn [17]

Answer:

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7 0

2 years ago

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KiRa [710]

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2 years ago

A thin film of oil of thickness t is floating on water. The oil has index of refraction no = 1.4. There is air above the oil. Wh

kkurt [141]

Answer:

t = 120.5 nm

Explanation:

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where n is the refractive index of oil

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for minimum thickness

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2 years ago

A physics professor is pushed up a ramp inclined upward at 30.0° above the horizontal as she sits in her desk chair, which slide

11111nata11111 [884]

Answer:

V = 3.17 m/s

Explanation:

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Initial Speed u = 2.00 m/s

Solution

Work = Change in kinetic energy

$F_{net}d = \frac{1}{2}mv^{2} - \frac{1}{2}mu^{2}\\\frac{2F_{net}d }{m} = v^{2} -u^{2}\\ v^{2} =\frac{2F_{net}d }{m} +u^{2}\\ v^{2} =\frac{2(600cos30 - 85\times 9.8 \times sin30) \times 2.5 }{85} +2.00^{2}\\ v^{2} = 10.066\\v = 3..17m/s$

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2 years ago