Answer:
a. 2.645 * 10^7 m/s^2
b. 2.645 * 10^4 N
Explanation:
Parameters given:
Velocity of rod = 2010m/s
Length of rod = 15.3cm = 0.153m
Mass of object placed at the end of the rod = 1g = 0.001kg
a. Centripetal acceleration is given as:
a = (v*v)/r
Where v = velocity
r = radius of curvature.
The radius of curvature in this case is equal to the length of the rod, since the rod makes the circular path of the motion.
Hence, centripetal acceleration at the end of the rod:
a = (2010*2010)/(0.153)
a = 26432156.86 m/s^2 = 2.64 * 10^7 m/s
b. The force needed to hold the object at the end of the rod is equal to the centripetal force at the end of the rod. Centripetal force is given as:
F = ma = (m*v*v)/r
Where a = centripetal acceleration
F = 0.001 * 2.64 * 10^7
F = 2.64 * 10^4N