Y-STR analysis. It is a DNA test used to compute and match with the possibility via lap.
Answer:
The magnitude of gravitational force between two masses is .
Explanation:
Given that,
Mass of first lead ball,
Mass of the other lead ball,
The center of a large ball is separated by 0.057 m from the center of a small ball, r = 0.057 m
We need to find the magnitude of the gravitational force between the masses. It is given by the formula of the gravitational force. It is given by :
So, the magnitude of gravitational force between two masses is . Hence, this is the required solution.
Answer:
the distance from charge A to C is r₁₃= 1.216 m
Explanation:
following Coulomb's law , the force exerted by 2 point charges between themselves is:
F= k*q₁*q₂/r₁₂² , where q is charge , r is distance and 1 and 2 represents the charge A and charge B respectively , k=constant
since C ( denoted as 3) is at equilibrium
F₁₃=F₂₃
k*q₁*q₃/r₁₃²=k*q₂*q₃/r₂₃²
q₁/r₁₃²=q₂/r₂₃²
r₁₃²/q₁=r₂₃²/q₂
r₂₃=r₁₃*√(q₂/q₁)
since C is at rest and is co linear with A and B ( otherwise it would receive a net force in either vertical or horizontal direction) , we have
r₁₃+r₂₃=d=r₁₂
r₁₃+r₁₃*√(q₂/q₁)=d
r₁₃*(1+√(q₂/q₁))=d
r₁₃=d/(1+√(q₂/q₁))
replacing values
r₁₃=d/(1+√(q₂/q₁)) = 3.00 m/(1+√(3.10 C/1.44 C)) = 1.216 m
thus the distance from charge A to C is r₁₃= 1.216 m
<h3><u>Answer;</u></h3>
<u> = 55.2 Coulombs </u>
<h3><u>Explanation</u>;</h3>
We can determine Charge using the formula
Q =It, where Q is the amount of charge in Coulombs, I is the current in amperes and t is the time in seconds.
I = 0.92 amperes, t = 1 minute or 60 seconds
Charge = 0.92 × 60
<u> = 55.2 Coulombs </u>
Is 3678.555667775 correct