If it was a double heterozygote, then aabb will be AaAaBbBb.
It will form 4 types of gametes since we have Aa, Bb. It will have aB, AB, ab, Ab.
An individual will form
only 2 type of gametes, Aa, Bb.
Genotype: 50% Aa and 50% aa
Phenotype: 50% Dimples and 50% no dimples
Explanation: Using a punnet square, we can figure out that the mother is recessive and the father is heterozygous. Putting the mother at the top of the square and the father on the side, you end up with the results above by crossing each square with the corresponding letters. It's okay if the letters end up backwards. Just be sure to face them the right direction, capitals being first once you finish.
Hope this helps!