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2 years ago

Please help! Will give brainliest for right answer!

Mathematics

1 answer:

KIM [24]2 years ago

8 0

The slope of the line, is the one with an variable, in this case x. The other value, 27.52, is the y intercept, which would represent how much money he began with. So the variable 17.63x represents how much he could expect to make per week. We know it is per week because there is only a single x, if there were two x's it would be per 2 weeks, three x's per 3 weeks and so on.

From this we can conclude the answer is B, Aidan can expect to save about $17.63 each week

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Pam has taken 4 tests. She scored an 82, 94, 89 and 92. What would she need to score on her 5th test to have a mean of 90?

zavuch27 [327]

Answer:

Step-by-step explanation:

5*90 = 450

82+94+89+92 = 357

450-357 = 93

hope this helped :)

5 0

2 years ago

The altitude of the triangle ABC, segment DA, has been

slavikrds [6]

Answer: sin(B)= h/c

h= csin(b)

Area= 1/2acsin(B)

Step-by-step explanation: i got the answers frfr on edge smh yall know how that is

3 0

2 years ago

Read 2 more answers

HELP plS! if sin 0=7/25, find cos0.

kodGreya [7K]

Hey there! :)

Answer:

csc θ = 25/7.

Step-by-step explanation:

Recall that csc, or cosecant, is the reciprocal of sine. Therefore:

If sin θ = 7/25:

Find the reciprocal:

7/25 --> 25/7.

csc θ = 25/7.

8 0

2 years ago

Read 2 more answers

Challenge:

bonufazy [111]

The trick here is that both times, part of the weight is soup
and part of the weight is the empty metal can.

1/2 soup + MTcan = 5
1/3 soup + MTcan = 4

Before going any further, it will make it a lot easier later if we change
the fractions in both equations to a common denominator:

1/2 = 3/6
1/3 = 2/6

3/6 soup + 1 MTcan = 5
2/6 soup + 1 MTcan = 4

Subtract the 2nd equation from the 1st one:

1/6 soup = 1

Multiply each side by 6 : 1 soup = 6

Substitute this in the first equation:

 1/2 soup + 1 MTcan = 5

 1/2 ( 6 ) + 1 MTcan = 5

 3 + 1 MTcan = 5

Subtract 3 from each side: 1 MTcan = 2

The empty can weighs 2.
All the soup it can hold weighs 6.

A full can of soup weighs (2 + 6) = 8

7 0

2 years ago

A bag contains red marbles, white marbles, and blue marbles. Randomly choose two marbles, one at a time, and without replacement

dsp73

Answer:

$P(First\ White\ and\ Second\ Blue) = \frac{3}{28}$

$P(Same) = \frac{67}{210}$

Step-by-step explanation:

Given (Omitted from the question)

$Red = 7$

$White = 9$

$Blue = 5$

Solving (a): $P(First\ White\ and\ Second\ Blue)$

This is calculated using:

$P(First\ White\ and\ Second\ Blue) = P(White) * P(Blue)$

$P(First\ White\ and\ Second\ Blue) = \frac{n(White)}{Total} * \frac{n(Blue)}{Total - 1}$

We used Total - 1 because it is a probability without replacement

So, we have:

$P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{21 - 1}$

$P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{20}$

$P(First\ White\ and\ Second\ Blue) = \frac{9*5}{21*20}$

$P(First\ White\ and\ Second\ Blue) = \frac{45}{420}$

$P(First\ White\ and\ Second\ Blue) = \frac{3}{28}$

Solving (b) $P(Same)$

This is calculated as:

$P(Same) = P(First\ Blue\ and Second\ Blue)\$ $or\ P(First\ Red\ and Second\ Red)\ or\ P(First\ White\ and Second\ White)$

$P(Same) = (\frac{n(Blue)}{Total} * \frac{n(Blue)-1}{Total-1})+(\frac{n(Red)}{Total} * \frac{n(Red)-1}{Total-1})+(\frac{n(White)}{Total} * \frac{n(White)-1}{Total-1})$

$P(Same) = (\frac{5}{21} * \frac{4}{20})+(\frac{7}{21} * \frac{6}{20})+(\frac{9}{21} * \frac{8}{20})$

$P(Same) = \frac{20}{420}+\frac{42}{420} +\frac{72}{420}$

$P(Same) = \frac{20+42+72}{420}$

$P(Same) = \frac{134}{420}$

$P(Same) = \frac{67}{210}$

6 0

2 years ago