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2 years ago

How to write standard form for: (please answer this question soon )

1 answer:

6 0

Put the terms in order of decreasing degree, all on the left. When convenient, it is nice to have mutually prime integer coefficients with the leading one positive.

a) x² -2x +1 = 0

b) x² +15 = 0

c) 4x² -12 = 0
or, better, divide out the common factor of 4.
x² -3 = 0

d) 3x² -x -5 = 0

_____
Shown is the standard form for a single-variable second-degree equation. Form varies depending on the nature of the equation. Equations of conic sections have different standard forms, depending on the curve.

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Someone help me out please

uysha [10]

1 step (B): raise both sides of the equation to the power of 2.

$(\sqrt{x+3}-\sqrt{2x-1})^2=(-2)^2,\\ (x+3)-2\sqrt{x+3}\cdot \sqrt{2x-1}+(2x-1)=4,\\ 3x+2-2\sqrt{x+3}\cdot \sqrt{2x-1}=4$ .

2 step (A): simplify to obtain the final radical term on one side of the equation.

$-2\sqrt{x+3}\cdot \sqrt{2x-1}=4-3x-2,\\ -2\sqrt{x+3}\cdot \sqrt{2x-1}=2-3x,\\ 2\sqrt{x+3}\cdot \sqrt{2x-1}=3x-2$ .

3 step (F): raise both sides of the equation to the power of 2 again.

$(2\sqrt{x+3}\cdot \sqrt{2x-1})^2=(3x-2)^2,\\ 4(x+3)(2x-1)=(3x-2)^2$ .

4 step (E): simplify to get a quadratic equation.

$4(2x^2-x+6x-3)=(3x)^2-2\cdot 3x\cdot 2+2^2,\\ 8x^2+20x-12=9x^2-12x+4,\\ x^2-32x+16=0$ .

5 step (D): use the quadratic formula to find the values of x.

$D=(-32)^2-4\cdot 16=1024-64=960, \\ \sqrt{D} =8\sqrt{5} ,\\ x_{1,2}=\dfrac{32\pm 8\sqrt{5}}{2} =16\pm 4\sqrt{5}$ .

6 step (C): apply the zero product rule.

$x^2-32x+16=(x-16-4\sqrt{5}) (x-16+4\sqrt{5}) ,\\ (x-16-4\sqrt{5}) (x-16+4\sqrt{5}) =0,\\ x_1=16+4\sqrt{5} ,x_2=16-4\sqrt{5}$ .

Additional 7 step: check these solutions, substituting into the initial equation.

3 0

2 years ago

13 If CDEF is a rhombus, find m FED.

Tatiana [17]

Answer:

Step-by-step explanation:

8x-20=5x+1

-5 -5

3x=-20+1

+20 +20

3x=21

3 3

x=7

8(7)-20

FED=36

8 0

1 year ago

What is the value of 8+ h² when h = 3?

MrMuchimi

Answer:

Step-by-step explanation:

8 + h^2

Let h = 3

8 + 3^2

We find the value of 3^2 first using PEMDAS

8 + 9

Then add

The result is 17

4 0

11 months ago

Read 2 more answers

If f(x) = x-1/3 and g(x)= 3x+1, what is (f o g)(x)?

N76 [4]

Answer:

$(f o g)(x) = 3x + \frac{2}{3}$

Step-by-step explanation:

We have the function $f(x) = x-\frac{1}{3}$ and we have the function $g(x) = 3x + 1$ . We want to find g(x) composed with f(x)

Then, the function (f o g)(x) is the same since f(g(x))

That is, you must do x = g(x) and then enter g(x) into the function f(x).

$f(g(x)) = (g(x)) -\frac{1}{3}$

$f(g(x)) = (3x + 1) -\frac{1}{3}$

Simplifying, we obtain:

$(f o g)(x) = 3x + 1 -\frac{1}{3}\\\\(f o g)(x) = 3x + \frac{2}{3}$

Finally. The composite function is:

$(f o g)(x) = 3x + \frac{2}{3}$

6 0

2 years ago

What is the perimeter of a lawn that is 25 feet long and 20 feet wide?

Inessa [10]

Answer:

Hey

Step-by-step explanation:

500 feet total is your answer because if you multiply the two numbers you et 500

7 0

2 years ago