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3 years ago

2. A certain object revolves at a rate of 30 rpm. Please determine the frequency and period of this

Physics

1 answer:

schepotkina [342]3 years ago

7 0

Answer:

The time period of the motion is, T = 0.03 s

The frequency of the rotation is, f = 30 Hz

Explanation:

Given data,

The rotational speed of an object, ω = 30 rpm

ω = 188.5 rad/s

The time period of motion is,

T = 2π / ω

Substituting the given values in the above equation

= 2π / 188.5

T = 0.03 s

The time period of the motion is, T = 0.03 s

The frequency of rotation,

f = 1 /T

= 1 / 0.03

= 30 Hz

Hence, the frequency of the rotation is, f = 30 Hz

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Answer:

Explanation:

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1 year ago

A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At

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The electric field of a very large (essentially infinitely large) plane of charge is given by:

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2 years ago

An amusement park ride consists of a rotating circular platform 11.1 m in diameter from which 10 kg seats are suspended at the e

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To solve this problem we will use the relationship given between the centripetal Force and the Force caused by the weight, with respect to the horizontal and vertical components of the total tension given.

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Matching both expressions with respect to the tension we will have to

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Then we have that,

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