Explanation:
Given that,
Charge 1,
Charge 2,
The distance between charges, r = 1.99 m
To find,
The electrostatic force and its nature
Solution,
(a) The electric force between two charges is given by :
(b) As the magnitude of both charges is positive, then the force between charges will be repulsive.
Therefore, this is the required solution.
Answer: 10^-3 V^2/Hz
Explanation:
1 Hz:
Su(f) = No * |H(f)|^2
= 10^-3 * 1/(1+(2*pi*f*R*C)^2)
= 10^-3 V^2/Hz
Answer:
The charge on each electrode is
Explanation:
The charge to find the equation is development
V=9v
Answer:
The work done is 10.64Joules
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