Question

Calculate the mass percent by volume of 330.1 g of glucose (C₆H₁₂O₆, MM = 180.2 g/mol) in 325 mL of solution.

Answer 1

Answer: The mass percent by volume is 101.6%

Explanation:

The solution concentration expressed in percent by volume means that the amount of solute present in 100 parts volume of solution.

It is represented in formula as :

mass percent by volume =$\frac{\text {mass of solute}\times 100}{\text {Volume of solution in ml}}\%$

Given : mass of glucose = 330.1 g

volume of solution = 325 ml

Thus mass percent by volume =$\frac{330.1g\times 100}{325ml}=101.6\%$

Thus the mass percent by volume is 101.6%