The set of values of the independent variable(s) for which a function or relation is defined. Typically, this is the set of x-values that give rise to real y-values. Note: Usually domain means domain of definition, but sometimes domain refers to a restricted domain.
Answer:
PR = 10
Step-by-step explanation:
PR =
The coordinates for P and R are (0,4) and (-6,-4) respectively.
So you plug in the values:
PR =
PR =
PR =
PR =
PR = 10
The correct answer for the completion exercise shown above is: sine.
Therefore, the complete text is shown below: "<span>In a right triangle, the sine of an angle can be found by dividing the length of the opposite leg by the length of the triangle's hypotenuse".
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A right triangle is a triangle that has an angle of 90 degrees.
The sine is one of the most common trigonometric functions. Therefore, you have that the sine of an angle is:
Sin(α)=opposite/hypotenuse
Answer:
Max is 4 days.
Step-by-step explanation:
An inequality is a math statement with more the one solution. The solution has a range of values for which the inequality can be satisfied. It has the same following components as an equation: variables and operations. However, the equal sign is replaced by an inequality sign: .
We start by choosing a variable for an unknown value. Here is it the number of days he rents the car. We choose d.
We know he rents it for $21 pr day or 21d for any number of days. We also know her will drive 250 miles at $0.10 per mile or 0.10(250). We will combine the two into an expression.
21d + 0.10(250)
We know his limit is $115. This means he can rent the car for any number of days until he reaches $115. The charge must be less than or equal to 115.
So we write .
To find the number of days he can rent the car, we solve for d using inverse operations.
This means Jim can rent the car up to 4 days. The 5th day will put the cost over $115.
Answer:
3927 cm² wrapping paper will be required.
Step-by-step explanation:
Lateral surface area of a cone shaped wrapper = πrl
where, r = radius of the waffle cone
and l = slant height of the cone
It has been given in the question, radius 'r' = 5cm
and lateral height 'l' = 10 cm
Lateral surface area of the cone = π(5)(10)
= 50π
= 157.08 cm²
If they plan to make 25 waffles then wrapper paper required
= 25×157.08
= 3927 cm²
Therefore, 3927 cm² wrapping paper will be required.