This problem deals with a weighted average. Since the AP classes count twice as much as regular classes, their grades must be counted twice. It's as if for each AP class he's taking, he was taking two classes. The points of each AP class grade is added twice, and the each AP class counts as 2 classes in the number of classes.
Each AP class counts twice and counts as 2 classes.
Class Ben's grade Points Number of Classes
AP English B 3 + 3 2
AP Government B 3 + 3 2
AP Algebra II A 4 + 4 2
Spanish B 3 1
Physics D 1 1
TOTALS 24 8
GPA = (total points)/(number of classes) = 24/8 = 3
<span>Answer: B 3.0</span>
Answer:Teo's age = 7 years ,Richard's age = 19 years
Step-by-step explanation:
Step 1
Let Teo's age be represented as x
Such that Richard 's age = 5 + 2x
and their combined ages equaling 26 can be expressed as
x + 5+ 2x = 26
Step 2 --- SOLVING
x + 5+ 2x = 26
3x+ 5= 26
3x= 26-5
3x= 21
x = 21/3
x = 7
Teo's age = 7 years
Richard's age = 5+2x= 5 + 14= 19 years
Step-by-step explanation:
(-6x +3y=9 )×4
( 10x+4y)×3
-24x +12y =36
30x+12y= -18
-24x+12y- (30x+12y)= 36-(-18)
-54x = 54
x= -1
by using 10x +4y = -6
apply x= -1
-10+4y= -6
4y= -6 +10
4y=4
y=1
so the answer is x=-1 and y= 1
The partial products are 4x80 and that's all because in the ones it has no actual digit
Answer:
40+39=79
Step-by-step explanation:
10 times 4+30+9
40*39=79
