The answer first of all, we should know that NaOH is a strong base. For such a product, the conentration of the OH - is equivalent to the concentration of the NaOH itself. that means: [ OH -] = [ NaOH] =<span>0.001 62 and for a strong basis, pH can be calculated as pH = 14 + log </span>[ OH -] first we compute log [ OH -] : log [ OH -] = log (0.001 62)= -2.79
