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2 years ago

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An isotope of potassium with a half-life of roughly one billion years is often used in radioactive dating. This isotope decays t

hrough electron capture, the process of drawing an electron into the nucleus. What is the chemical symbol for the element that results from this process? The equation for the reaction is 4019K+ 0−1e→?. Express your answer as a chemical symbol (e.g., Na for sodium).

1 answer:

melisa1 [442]2 years ago

7 0

Answer : The chemical symbol for the element that results from this process is, (Ar) for argon.

Explanation :

Electron capture : In this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. Simply, a proton and an electron combines together to form a neutron. Mass number does not change in this process.

$_Z^A\textrm{X}+_{-1}^0\textrm{e}\rightarrow _{Z-1}^A\textrm{Y}$

The equation for the given reaction is,

$_{19}^{40}\textrm{K}+_{-1}^0\textrm{e}\rightarrow _{18}^{40}\textrm{Ar}$

Thus, the chemical symbol for the element that results from this process is, argon (Ar).

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Calculate the solubility of carbon dioxide in water at an atmospheric pressure of 0.400 atm (a typical value at high altitude).A

Bond [772]

Answer:

The molar solubility of carbon dioxide gas is $4.662\times 10^{-6} M$ .

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{CO_2}=K_H\times p_{liquid}$

where,

$K_H$ = Henry's constant = $3.50\times 10^{-2}mol/L.atm$

$p_{CO_2}$ = partial pressure of carbonated drink

$p_{CO_2}=p\times \chi_{CO_2}$

where = p = Total pressure = 0.400 atm

$\chi_{CO_2}$ = mole fraction of $CO_2=3.33\times 10^{-4}$

$p_{CO_2}=0.400 atm\times 3.33\times 10^{-4} =0.0001332 atm$

Putting values in above equation, we get:

$C_{CO_2}=3.5\times 10^{-2}mol/L.atm\times 0.0001332 atm\\\\C_{CO_2}=4.662\times 10^{-6} M$

Hence, the molar solubility of carbon dioxide gas is $4.662\times 10^{-6} M$ .

8 0

2 years ago

List of 10 strong bases and acids?

tatyana61 [14]

<span><span>KaAcid</span><span><span>1.0 * 109</span>Hydrobromic acidHBr</span><span><span>1.3 * 106</span>Hydrochloric acidHCl</span><span><span>1.0 * 103</span>Sulfuric acid<span>H2SO4</span></span><span><span>2.4 * 101</span>Nitric acid<span>HNO<span>3</span></span></span></span>

4 0

2 years ago

A patient needs 40.0 mg of antibiotic per kilogram of body weight each day. If the patient weighs 55 kilograms.

White raven [17]

2200 mg of antibiotic

Explanation:

Given that 40 mg of antibiotic/kg of the bodyweight is given.

If patient is 55 kg then the dose of antibiotic will be

if 40/1000000 is done then we can get antibiotic in kg/kg of the weight

= 0.00004 kg of antibiotic per kg

0.00004*55 ( to know how much 55 kg person will require)

= 0.0022 kg

This 0.0022 value will be converted to mg

0.0022*10^6

= 2200 mg of antibiotic will be given to a 55kg patient.

4 0

2 years ago

In the system model, the direction of the<br> arrow tells you that

AlladinOne [14]

Answer: Answer b

Explanation:

4 0

2 years ago

Read 2 more answers

We make a basic solution by mixing 50. mL of 0.10 M NaOH and 50. mL of 0.10 M Ca(OH)2. It requires 250 mL of an HCl solution to

andreyandreev [35.5K]

<u>Answer:</u> The correct answer is Option 5.

<u>Explanation:</u>

To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

$M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of the NaOH.

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of the $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL$

Putting all the values in above equation, we get:

$M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M$

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base.

We are given:

$n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL$

Putting values in above equation, we get:

$1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M$

Hence, the correct answer is Option 5.

7 0

2 years ago