Write the equation of the line that passes through the points (-1,-5) and (2,4).

Mathematics

2 answers:

rusak2 [61]3 years ago

7 0

The answer is: y=3x+1

Art [367]3 years ago

3 0

Answer:

y=3x+1

Step-by-step explanation:

First, we have to find the slope. $\frac{4-(-5)}{2-(-1)}$ This comes out to 9/3. This becomes 3. Now we need to find the y-intercept. Now write out how to find the answer. 4=3(2)+b. 4=3+b. Subtract 3 from both sides to get 1=b. Now write out the equation. y=3x+1

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Factor this expression completely, then place the factors in the proper location on the grid. a^3y + 1

ivolga24 [154]

Answer:

$a^{3y} + 1 = (a^{y}+1 )^{3} - 3a^y(a^{y}+1)\\\\$

Step-by-step explanation:

We are to factorize the expression $a^{3y} + 1$ completely. To do this, we will apply the expression below;

The expression can be rewritten as $a^{3y} + 1^{3}$

To factorize the expression, we need to first factorize $(a^{y}+1 )^{3}$ first

$(a^{y}+1 )^{3} =(a^{y}+1 )(a^{y}+1 )^{2}\\= (a^{y}+1 )((a^y)^{2} } + 2a^{y} +1)\\= (a^y)^{3} +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y+1\\(a^{y}+1 )^{3} = ((a^y)^{3} + 1) +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y\\(a^{y}+1 )^{3} = ((a^y)^{3} + 1) +3(a^y)^{2}+3a^y\\$