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1 year ago

Given:

1 answer:

3 0

A line bisector is a straight line that divides a given line into two equal parts. Thus the following steps are required by Naomi to show that point D is equidistant from points A and C.

BD ⊥ AC (given)

BD = 3 units, and AC = 8 units.

BD is the perpendicular bisector of segment AC (given)

Thus,

<BDA ≅ <BDC (right angles formed by a perpendicular bisector)

AD ≅ DC (equal parts of a bisected line)

AD ≅ DC = 4 units

Thus joining points B to A, and B to C,

BA ≅ BC.

So that applying Pythagoras theorem to ΔABD, we have:

$/hyp/^{2}$ = $Adj 1^{2}$ + $Adj 2^{2}$

$AB^{2}$ = $3^{2}$ + $4^{2}$

= $\sqrt{25}$

AB = 5 units

So that,

BA ≅ BC = 5 units

Therefore, it can be concluded that point D is equidistant from points A and C.

For more clarifications on a perpendicular bisector of a line, visit: brainly.com/question/929137

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If 10+6/x=22 what is the value of x

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Answer:

x=8/11

Step-by-step explanation:

10+6/x=22

16/x=22

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x=16/22

x=8/11

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Can someone help me with this question? Thank you!

Harrizon [31]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's evaluate ~

The given expression is :

$\qquad \sf \dashrightarrow \:4x + 8$

plug the value of x as 3

$\qquad \sf \dashrightarrow \:4(3) + 8$

$\qquad \sf \dashrightarrow \:12 + 8$

$\qquad \sf \dashrightarrow \:20$

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1 year ago

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

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2 years ago

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Lostsunrise [7]

Answer:

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Step-by-step explanation:

This is pretty complex math for middle school with logarithms and what not. Make sure you typed the problem in correctly. If you did, I guess that's your answer.

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