The statement is false, as the system can have no solutions or infinite solutions.
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Is the statement true or false?</h3>
The statement says that a system of linear equations with 3 variables and 3 equations has one solution.
If the variables are x, y, and z, then the system can be written as:
Now, the statement is clearly false. Suppose that we have:
Then we have 3 parallel equations. Parallel equations never do intercept, then this system has no solutions.
Then there are systems of 3 variables with 3 equations where there are no solutions, so the statement is false.
If you want to learn more about systems of equations:
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If you mean 46 * 3 = 138
If you mean 46 + 3 = 49
If you mean 46 - 3 = 43
If you mean<span> 46 ÷ 3 = 15.3
Hope it helped
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Y - 2 = -3/4 (x - 6)
y = -3/4 (x - 6) + 2
When, x = -2,
y = -3/4 (-2 - 6) + 2 = -3/4 (-8) + 2 = 6 + 2 = 8
One point is (-2, 8)
When, x = 2,
y = -3/4 (2 - 6) + 2 = -3/4 (-4) + 2 = 3 + 2 = 5
Another point is (2, 5)
Answer:
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Step-by-step explanation:
u = kx + ух
First of all factorize x out at the right side of the equation
That's
u = x(k + y)
Divide both sides by ( k + y) to make x stand alone
That's
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We have the final answer as
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Hope this helps you